Find ∫ [c o t x + t a n x ] d x Answer ∫ [ cot x + tan x ] d x ⇒ ∫ [ cot x + c o t x 1 ] d x ⇒ ∫ [ c o t x c o t x + 1 ] d x ⇒ ∫ [ tan x ( cot x + 1 ) ] d x L e t tan x = t 2 d i f f . w . r . t . x , S e c 2 x = 2 t d x d t ( 1 + tan 2 x ) = 2 t . d x d t ⇒ 1 + ( t 2 ) 2 = 2 t . d x d t ⇒ ( 1 + t 4 ) d x = 2 t d t ⇒ d x …

VE ,sin x dxalar(AIEEa) xx - 108 sin (--)|+c(ii) x 105 |cos (-4)+cb) x + tog sin (x-4)+c(iv) x + log |cos (x-)| sin2xsin2x+2cos2x dx (i) -log(1+sin2x)+C (ii) log(1+cos2x)+C (iii) -log(1+cos2x)+C (iv) log(1+tan2x)+C int cos(log x)dx is equal to (A)(x).

= [2 ln u ]10. 1. = [ 1. 3 u3] 1. 1.

Tan2 x dx

} = ∫. 1 + tan2(x) = 1 cos2(x) cos(2x) = cos2(x) − sin2(x) sin(2x) = 2 sin(x) cos(x) sin xdx. = − cos x + C. ∫ cos xdx. = sin x + C. ∫. 1 cos2x dx. = tan x + C. ∫. 1.

1+x2. vara mig tillhanda senast den 12:e december.

1 2 1 tan 2 24 dx x C x = + + 6. 2 ,x x u e du e dx= + = 2 x x e du dx ue = + ln u C= + ln 2 ln(2 ) x x e C e C = + + = + + 7. 2 4,u x= + du = 2x dx 2 1

∫ x tan2x dx - Slader. integration of 1 + tan^2x can be written x + tan^3/3 isn't it?

let's see if we can evaluate the indefinite integral of tangent X DX and so like always pause the video and see if you can figure it out on your own and I will give

Best answer.

check-circle. Answer. Step by step solution by experts to help you in doubt clearance Solved: Evaluate the integral. ∫ x tan2x dx - Slader.
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3 e u = x2 − 3 ∴ d d u x. = 2x f u = x3 + f(x) dx kallas integralen av f(x) dx och betecknar en godtycklig primitiv dvs om vi deriverar integralen av f(x) dx får vi tillbaka integranden f(x). 1 − tan2 (x2).

Stack Exchange Network Stack Exchange network consists of 176 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. Solved: Integrate: \int \tan^{2} x \sec^{4} x dx By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can 2014-09-12 $$\int sec^2x \tan^2x dx = tan^2x - 2\int \sec^2x \tan^2x dx$$ You can move the $- 2\int \sec^2x \tan^2x dx$ to the left hand side of the equation by addition.
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In (tan^2)x your 1st mistake is not writing dx. Note that dx is NOT always du!!!!! If you let u=tanx in integral (tan^2)x you get integral u^2 dx which is not (u^3)/3 + c since du= sec^2x dx

−. = 2 ln 10 − 0. = 1. 3 [1 − (−1)]. = 2 ln 10. = 2.

∫ tan 2 x(1 + tan 2 x) dx ∫(tan 2 x)(sec 2 x) dx ∫ (tanx)(tanx)(sec 2 x) dx. Let u = tanx then du = sec 2 x dx. then integral becomes

1. 1 + 4x 2. dx. (3). 2: 4.

x ) = 0 dr ( 4 ) maa være et partikulært Integral af hin . Substitueres da i ( 2 ) d d : B dx V ( 5 ) ændres denne til ( 6 ) d d 0 , dx uden Hensyn til om Gå över till den naturliga exponentialfunktionen: 2x=(eln2)x=exln2. 9.2.g) \int\sin 2x\cos 2x\, dx=\frac{1 Eftersom 1+tan2x=1 cos2x , så är. 3. 414 Section 7.1 Instructors Resource Manual 22. 2 ,u x= du = 2x dx 4 2 1 24 4 x du dx x u = + + 11 tan 4 2 u C = + 2 11 tan 4 2 x C = + 23.